Set already has 1 as item True evaluates to 1. As you know set doesn’t allow duplicate element

Question was not answered

A = {30, 20, 10}
B = {50, 30, 40}
print(A.symmetric_difference(B))

{40, 10, 50, 20}

The difference() method returns a set that contains the difference between two sets.
Here set3 = set2.difference(set1) so the returned set contains items that exist only in the first set, and not in both sets.

The difference_update() method removes the items that exist in both sets. Here set1.difference_update(set2) removed the unwanted items from the original set1.

Python set doesn’t allow duplicate items.

We cannot access items in a set by referring to an index because the ‘set’ object does support indexing (the set is unordered). if you try to access items using the index, you will get TypeError: ‘set’ object does not support indexing.

Use a for loop to access set items.

sampleSet = {"Yellow", "Orange", "Black"}
for item in sampleSet:
  print(item)

If you try to execute the above code you will get a TypeError: unhashable type: 'list'

• It is true that the set itself is changeable (mutable), but it cannot contain changeable objects such as list and dictionary.
• Python set can contain unchangeable objects like number, string, tuple etc

The remove() and discard() method removes the specified item from a set.