How do you sort a list in Python?

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Answer:

There are several ways to sort a list in Python, depending on your specific requirements.

The most straightforward way to sort a list is to use the built-in sorted function. The sorted function takes a list as an argument and returns a new list containing the elements of the original list, sorted in ascending order:

# Original list
original_list = [3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5]

# Sorted list
sorted_list = sorted(original_list)

print("Original list:", original_list)
print("Sorted list:", sorted_list)

Output:

Original list: [3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5]
Sorted list: [1, 1, 2, 3, 3, 4, 5, 5, 5, 6, 9]

If you need to sort the list in descending order, you can pass the reverse=True argument to the sorted function:

# Sorted list in descending order
sorted_list = sorted(original_list, reverse=True)

print("Sorted list in descending order:", sorted_list)

Output:

Sorted list in descending order: [9, 6, 5, 5, 5, 4, 3, 3, 2, 1, 1]

Another way to sort a list is to use the sort method of the list object. The sort method sorts the list in-place and returns None, so you need to call it on the list you want to sort:

# Sort the original list in-place
original_list.sort()

print("Original list:", original_list)

Output:

Original list: [1, 1, 2, 3, 3, 4, 5, 5, 5, 6, 9]

Just like the sorted function, you can also sort the list in descending order using the sort method by passing the reverse=True argument:

# Sort the original list in-place in descending order
original_list.sort(reverse=True)

print("Original list:", original_list)

Output:

Original list: [9, 6, 5, 5, 5, 4, 3, 3, 2, 1, 1]

Note that the sort method modifies the list in-place, so if you need to keep the original list intact, you should use the sorted function instead.

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