Logic to print the given number pattern<pre style=
C Programming Language / Loop control in C Language
4619Program:
/** * C program to print number pattern * www.atnyla.com */ #include int main() { int i, j, N; printf("Enter N: "); scanf("%d", &N); for(i=1; i<=N; i++) { // Logic to print numbers for(j=1; j<=N-i+1; j++) { printf("%d", j); } printf("\n"); } return 0; }
Output:
Enter N: 5 12345 1234 123 12 1
Explanation:
Logic to print the given number pattern 1
12345 1234 123 12 1
To understand the logic of given pattern, I recommend you to have a careful look of the pattern for a minute. Now talking about the pattern, there are N number of rows (where N is given by user). Each row contains exactly N - i + 1 number of columns (where i is the current row number). And for each row in each column the value of j gets printed (where j is the current column number).
The step-by-step descriptive logic of the given pattern:
- To iterate through rows, start an outer loop from 1 to N.
- To print the numbers, start an inner loop from 1 to N - i + 1. Inside this loop print the value of
j.
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