C program to print reversed mirrored right triangle star pattern
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C Programming Language / Loop control in C Language
994Program:
/** * C program to print reverse mirrored right triangle star pattern * atnyla.com */ #include int main() { int i, j, rows; /* Input rows from user */ printf("Enter number of rows: "); scanf("%d", &rows); /* Iterate through rows */ for(i=1; i<=rows; i++) { /* Print leading spaces */ for(j=1; j
Output:
Enter number of rows: 5 **** *** ** *
Explanation:
Required knowledge
Basic C programming, For loop, Nested loop
Must know - Program to print inverted right triangle star pattern.
Logic to print reversed mirrored right triangle star pattern
***** **** *** ** *
The above pattern is similar to inverted right triangle star pattern with leading spaces. The pattern consist of N rows and each row contains N - i + 1
stars. In addition to stars each row contains some leading spaces. For each row there are total i - 1
spaces (where i is current row number). Point your mouse cursor over the above pattern to count total spaces per row.
Step by step descriptive logic to print reversed mirrored right triangle star pattern.
- Input number of rows to print from user. Store it in a variable say rows.
- To iterate through rows, run an outer loop from 1 to rows. The loop structure should look like
for(i=1; i <= rows; i++)
. - To print spaces, run an inner loop from 1 to
i - 1
. The loop structure should look likefor( j=1; j < i; j++ )
. Inside this loop print single space.Note:
j < i
is equivalent toj <= i - 1
. - To print stars, run another inner loop from i to rows. The loop structure should look like
for( j=i; j <= rows; j++)
. Inside the loop print star. - After printing all columns of a row, move to next line i.e. print new line.
Another Way to do the above program
/* * C program to print right triangle star pattern series * atnyla.com */ #include int main() { int i, j, n; /* Input number of rows from user */ printf("Enter value of n: "); scanf("%d", &n); for(i=1; i<=n; i++) { /* Print i number of stars */ for(j=1; j<=n; j++) { if(i<=j) printf("*"); else printf(" "); } /* Move to next line */ printf("\n"); } return 0; }
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