C program to print chessboard number pattern with 1 and 0 
10101
01010
10101
01010
10101

C Programming Language / Loop control in C Language

12470

Program:

/**
 * C program to print box number pattern with cross center
 *  www.atnyla.com
 */

#include <stdio.h>

int main()
{
    int rows, cols, i, j, k;

    /* Input rows and columns from user */
    printf("Enter number of rows: ");
    scanf("%d", &rows);
    printf("Enter number of columns: ");
    scanf("%d", &cols);

    k = 1;

    for(i=1; i<=rows; i++)
    {
        for(j=1; j<=cols; j++)
        {
            if(k == 1)
            {
                printf("1");
            }
            else
            {
                printf("0");
            }

            // If k = 1  then k *= -1 => -1
            // If k = -1 then k *= -1 =>  1
            k *= -1;
        }

        if(cols % 2 == 0)
        {
            k *= -1;
        }

        printf("\n");
    }

    return 0;
}
Output

Output:

Enter number of rows: 5
Enter number of columns: 5
10101
01010
10101
01010
10101

Explanation:

Required knowledge

Basic C programming, Loop

Logic to print chessboard number pattern

If you think the above pattern as a matrix, then 1 and 0 is printed at every alternate element. To keep track of alternate element we will use an extra variable say k. k can have two possible values i.e. -1 and 1. For k = 1 print 1 otherwise print 0.
Below is the step by step descriptive logic to print the given pattern.

  1. Input number of rows and columns to print from user. Store it in some variable say rows and cols.
  2. Initialize a variable to keep track of alternate element, say k = 1.
  3. To iterate through rows run an outer loop from 1 to rows. The loop structure should look like for(i=1; i<=rows; i++).
  4. To iterate through columns run an inner loop from 1 to cols. The loop structure should look like for(j=1; j<=cols; j++).
  5. Inside the inner loop print 1, 0 for alternate elements. Say if(k == 1) then print 1 otherwise 0. After printing change the value of k = k * -1.
  6. Finally, move to next line after printing all columns of a row.

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