Q: What is the output of this C code?

    void main()
    {
        int x = 97;
        int y = sizeof(x++);
        printf("X is %d", x);
    }

 

Answer: A

Option A

The output of the given C code would be:

X is 97

In the code, x is assigned the value 97. The line int y = sizeof(x++); attempts to get the size (in bytes) of the expression x++, which is a post-increment operation on x. The sizeof operator is evaluated at compile time and doesn't actually increment x.

So, even though the sizeof(x++) line appears to increment x, the value of x remains 97, and the output prints "X is 97". The increment operation within sizeof doesn't affect the value of x in this case.

Click me to Read more Question & Answer of Pointer in C Language

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