Q:

What will be output when you will execute following c code?

#include<stdio.h>
   int main(){
    signed x,a;
    unsigned y,b;
    a=(signed)10u;
    b=(unsigned)-10;
    y = (signed)10u + (unsigned)-10;
    x = y;
    printf("%d  %u\t",a,b);
    if(x==y)
         printf("%d %d",x,y);
    else if(x!=y)
         printf("%u  %u",x,y);
    return 0;
}

 

Answer: C

Output of Turbo C++ 3.0: 10 65526 0 0

10 65526 0 0

Turbo C ++4.5: 10 65526 0 0

10 65526 0 0

Linux GCC: 10 4294967286 0 0

10 4294967286 0 0

Visual C++: 10 4294967286 0 0

10 4294967286 0 0

a=(signed)10u;

signed value of 10u is +10

so, a=10

b=(unsigned)-10;

unsigned value of -10 is :

MAX_VALUE_OF_UNSIGNED_INT – 10 + 1

In turbo c 3.0 complier max value of unsigned int is 65535

So, b = 65526

y = (signed)10u + (unsigned)-10;

= 10 + 65526 = 65536 = 0 (Since 65536 is beyond the range of unsigned int. zero is its corresponding cyclic vlaue)

X = y = 0

Click me to Read more Question & Answer of Data Types in C Language

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