Q: A and B are argentum and brass alloys made by combining metals in amounts of 7: 2 and 7: 11, respectively. When equal amounts of the two alloys are melted to make a third alloy C, the percentage of argentum and brass in C is?

A 7 : 5
B 7 : 9
C 2 : 5
D 7 : 3
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Answer: A


The first alloy is prepared by mixing metals in proportions 7 : 2,
Then the weight of the first alloy will be = 7x + 2x
Assume ’x’ = 1Kg
The weight of the first alloy will be 9kg
The second alloy is prepared by mixing metals in proportions 7 : 11,
The weight of the second alloy will be 18kg
If equal quantities of the two alloys are melted to form a third alloy,
Then 18Kg of first alloy should be used, then its ratio will become 14 : 4,
Now, the proportion of argentum and brass in third alloy = 7 + 14 : 11 + 4 = 21 : 15 = 7 : 5

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