Arithmetic Aptitude Problems on Ages

• A 40
• B 35
• C 30
• D 26
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B

Answer: B

Let P's present age be 3x and Q's present age be 4x. Ten years ago, P's age was half of Q's age, so we can write this as: (3x - 10) = 1/2(4x - 10) Solving for x, we get: 6x - 20 = 4x - 10 2x = 10 x = 5 Thus, the total of their present ages is 7x = 7 * 5 = 35.

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