Q: If the mother's age 10 years ago was 3 times the age of her son, and in 10 years the mother's age will be twice the age of her son, what is the ratio of their present ages?

A 11:7
B 7:4
C 7:3
D 9:5
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Answer: C


 If the age of the mother 10 years ago was 3 times the age of her son,
 and the mother's age in 10 years will be twice the age of her son,
 
the equation can be represented as:

3x+10+10=2(x+10+10)
3x+20=2x+40
x=20

The present ratio of the mother's age to the son's age is 

(3x+10):(x+10) = (3*20+10):(20+10) = 70:30 = 7:3.



                                  
                                  
                                  
                                    
                                      
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