Q: A and B can do the work in 40 days and 30 days, respectively. After A worked alone for 10 days, B worked for an additional 10 days. C then finished the remaining work in 10 days. How many days would it take C to do the entire job on their own?  

Answer: B

To solve this equation, we can use algebraic methods. Here's how you can solve for x:
First, we start with the equation 10/40 + 10/30 + 10/x = 1.
We can simplify each fraction by dividing the numerator and denominator by their greatest common factor, which gives us (1/4) + (1/3) + (10/x) = 1.
Now we can add (1/4) and (1/3) to get (7/12) + (10/x) = 1.
Subtracting (7/12) from both sides of the equation gives us (10/x) = (5/12).
Multiplying both sides of the equation by x gives us 10 = (5/12) * x.
Multiplying both sides of the equation by 12/5 gives us x = 24.
So, the solution to the equation is x = 24.
This means that it would take C alone 24 days to do the entire job

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