Q: A tiger lags behind a deer by 50 jumps. The tiger has 5 jumps per minute compared to the deer's 4. What distance will the tiger have to sprint before catching the deer if the tiger and the deer cover 8 m and 5 m every leap, respectively?

A 600 m
B 800 m
C 1000 m
D 900 m
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Answer: B


The tiger takes 5 leaps per minute and the deer takes 4 leaps per minute.

The speed of the tiger can be calculated using the formula speed = number of leaps per minute x distance covered per leap, which gives us speed = 5 leaps/minute x 8 meters/leap = 40 meters/minute.

The speed of the deer can be calculated using the formula speed = number of leaps per minute x distance covered per leap, which gives us speed = 4 leaps/minute x 5 meters/leap = 20 meters/minute.

The tiger is 50 leaps behind the deer, which is equivalent to a distance of 50 leaps x 8 meters/leap = 400 meters.

The relative speed of the tiger and deer is given as 20 meters/minute.

The time taken by the tiger to catch the deer can be calculated using the formula time = distance / speed, which gives us time = 400 meters / 20 meters/minute = 20 minutes.

The distance traveled by the tiger before it catches the deer can be calculated using the formula distance = speed x time, which gives us distance = 40 meters/minute x 20 minutes = 800 meters.

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