Q: Two 100-meter-long trains are travelling in opposing directions. They will cross in 8 seconds. If one train travels twice as quickly as the other, the faster train's speed is

A 35 km/hr
B 70 km/hr
C 45 km/hr
D 60 km/hr
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Answer: D


The total distance covered by the two trains is given as 200 meters.

The time taken for the trains to pass each other is given as 8 seconds.

The speed of the slower train is given as v km/hr and the speed of the faster train is given as 2v km/hr.

The relative speed of the two trains is the sum of their individual speeds, which is given as 3v km/hr.

We can use the relative speed, total distance covered, and time taken to find the speed of the two trains. Since the relative speed is 3v km/hr and the total distance covered is 200 meters, we can set up the following equation: 3v = 200/8 m/s = 25 m/s.

Solving for v, we get v = 25/3 m/s.

The speed of the faster train is given as 2v km/hr. Plugging in the value of v that we found in step 6, we get the speed of the faster train as 2v = (50/3) * (36/10) km/hr = 5 * 36/3 = 5 * 12 = 60 km/hr.

Therefore, the speed of the slower train is 25/3 m/s and the speed of the faster train is 60 km/hr.

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